Columb's Law (By pak physics notes)

STATEMENT

The electrostatic force of attraction or repulsion between two point charges is directly proportional      to the product of charges inversely proportional to the square of distance between them.

Explanation

Consider two point charges q1 and q2 at a placed distance of r from each other. Let the electrostatic force between them is F.

According to the first part of the law:

                                                                            F α q₁q₂

According to the second part of the law:                                                                              F α 1/r2 Combining above statements:                                                                              F α q1q2/r2                                                                              F =k q1q2/r2   --------------------(1) Where k is the constant of proportionality. Value of K is equal to 1/4pe0 where eo is permittivity of free space .Its volume is 8.85 x 10-12 c2/Nm2. Thus in S.I. system numerical value of K is 8.98755 x 109 Nm2c-2. Putting the value of K = 1/4pe0 in equation (i)                                                                                                                                F = 1/4pe0 q1q2/r2 FORCE IN THE PRESENCE OF  DIELECTRICMEDIUM If the space between the charges is filled with a non conducting medium or an insulator called "dielectric", it is found that the dielectric reduces the electrostatic force as compared to free space by a factor (er) called DIELECTRIC CONSTANT. It is denoted byer . This factor is also known as RELATIVE PERMITTIVITY. It has different values for different dielectric materials.                     (www.pak-physicsnotes.blogspot.com)

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