The first practical demonstration of optical interference was provided by THOMAS YOUNG in 1801. His experiment gave a very strong support to the wave theory of light.
Arrangement of Experiment
'S' is a slit, which receives light from a source of monochromatic light. As 'S' is a narrow slit so it diffracts the light and it falls on slits A and B. After passing through the two slits, interference between two waves takes place on the screen. The slits A and B act as two coherent sources of light. Due to interference of waves alternate bright and dark fringes are obtained on the screen.
Experiment
Let the wave length of light = l
Distance between slits A and B = d
Distance between slits and screen = L
Consider a point 'P' on the screen where the light waves coming from slits A and B interfere such that PC=y. The wave coming from A covers a distance AP=r1 and the wave coming from B covers a distance BP=r2 such that PB is greater than PA.
Distance between slits A and B = d
Distance between slits and screen = L
Consider a point 'P' on the screen where the light waves coming from slits A and B interfere such that PC=y. The wave coming from A covers a distance AP=r1 and the wave coming from B covers a distance BP=r2 such that PB is greater than PA.
Path difference = BP-AP = BD | ||||||||||||||||||
S = r2-r1 = BD | ||||||||||||||||||
In right angled DBAD | ||||||||||||||||||
Sinq = BD/AB Or sinq = s/d Or S = dsinq -------(1) | ||||||||||||||||||
Since the value of 'd' is very very small as compared to L, therefore, q will also be very small. In this condition we can assume that : | ||||||||||||||||||
Sinq = tanq From (1) S = dtanq ---(2) In right angled DPEC Tanq = PC/EC = y/L Putting the value of tanq in eq. (2), w get S = dy/L Or y = SL/d -----(3)
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